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25d^2+25d+6=0
a = 25; b = 25; c = +6;
Δ = b2-4ac
Δ = 252-4·25·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*25}=\frac{-30}{50} =-3/5 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*25}=\frac{-20}{50} =-2/5 $
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