25g2-25g=-6

Solution for 25g2-25g=-6 equation:

25g^2-25g=-6

We move all terms to the left:

25g^2-25g-(-6)=0

We add all the numbers together, and all the variables

25g^2-25g+6=0

a = 25; b = -25; c = +6;
Δ = b2-4ac
Δ = -252-4·25·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5}{2*25}=\frac{20}{50}
=2/5
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5}{2*25}=\frac{30}{50}
=3/5
$