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25n+15n^2=6500
We move all terms to the left:
25n+15n^2-(6500)=0
a = 15; b = 25; c = -6500;
Δ = b2-4ac
Δ = 252-4·15·(-6500)
Δ = 390625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{390625}=625$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-625}{2*15}=\frac{-650}{30} =-21+2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+625}{2*15}=\frac{600}{30} =20 $
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