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25q^2=49
We move all terms to the left:
25q^2-(49)=0
a = 25; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·25·(-49)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*25}=\frac{-70}{50} =-1+2/5 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*25}=\frac{70}{50} =1+2/5 $
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