25t-1/5t=0

Solution for 25t-1/5t=0 equation:

25t-1/5t=0


Domain of the equation: 5t!=0

t!=0/5

t!=0

t∈R


We multiply all the terms by the denominator


25t*5t-1=0

Wy multiply elements

125t^2-1=0

a = 125; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·125·(-1)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{5}}{2*125}=\frac{0-10\sqrt{5}}{250}
=-\frac{10\sqrt{5}}{250}
=-\frac{\sqrt{5}}{25}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{5}}{2*125}=\frac{0+10\sqrt{5}}{250}
=\frac{10\sqrt{5}}{250}
=\frac{\sqrt{5}}{25}
$