25t2+70t+49=0

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Solution for 25t2+70t+49=0 equation:



25t^2+70t+49=0
a = 25; b = 70; c = +49;
Δ = b2-4ac
Δ = 702-4·25·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-70}{50}=-1+2/5$

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