25t=5(5t/1)

Solution for 25t=5(5t/1) equation:

25t=5(5t/1)

We move all terms to the left:

25t-(5(5t/1))=0

We add all the numbers together, and all the variables

25t-(5(+5t/1))=0

We multiply all the terms by the denominator


25t*1))-(5(+5t=0

We add all the numbers together, and all the variables

5t+25t*1))-(5(=0

Wy multiply elements

25t^2+5t=0

a = 25; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·25·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*25}=\frac{-10}{50}
=-1/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*25}=\frac{0}{50}
=0
$