25x(1.96)2x(0.5)x(0.5)/0.032X(25-1)+(1.96)2x(0.5)x(0.5)=N

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Solution for 25x(1.96)2x(0.5)x(0.5)/0.032X(25-1)+(1.96)2x(0.5)x(0.5)=N equation: 



25x(1.96)2x(0.5)x(0.5)/0.032x(25-1)+(1.96)2x(0.5)x(0.5)=

We move all terms to the left:

25x(1.96)2x(0.5)x(0.5)/0.032x(25-1)+(1.96)2x(0.5)x(0.5)-()=0



Domain of the equation: 0.032x(25-1)!=0

x∈R



We add all the numbers together, and all the variables

25x(1.96)2x(0.5)x(0.5)/0.032x24+(1.96)2x(0.5)x(0.5)-()=0

We add all the numbers together, and all the variables

25x(1.96)2x(0.5)x(0.5)/0.032x24+(1.96)2x(0.5)x(0.5)=0

We multiply all the terms by the denominator


25x(1.96)2x(0.5)x(0.5)+((1.96)2x(0.5)x(0.5))*0.032x24=0

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