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25x(5x-5)=-25+5x
We move all terms to the left:
25x(5x-5)-(-25+5x)=0
We add all the numbers together, and all the variables
25x(5x-5)-(5x-25)=0
We multiply parentheses
125x^2-125x-(5x-25)=0
We get rid of parentheses
125x^2-125x-5x+25=0
We add all the numbers together, and all the variables
125x^2-130x+25=0
a = 125; b = -130; c = +25;
Δ = b2-4ac
Δ = -1302-4·125·25
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-20\sqrt{11}}{2*125}=\frac{130-20\sqrt{11}}{250} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+20\sqrt{11}}{2*125}=\frac{130+20\sqrt{11}}{250} $
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