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25x(x+1)+4=0
We multiply parentheses
25x^2+25x+4=0
a = 25; b = 25; c = +4;
Δ = b2-4ac
Δ = 252-4·25·4
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-15}{2*25}=\frac{-40}{50} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+15}{2*25}=\frac{-10}{50} =-1/5 $
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