25x+8=1/4x+8

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Solution for 25x+8=1/4x+8 equation:



25x+8=1/4x+8
We move all terms to the left:
25x+8-(1/4x+8)=0
Domain of the equation: 4x+8)!=0
x∈R
We get rid of parentheses
25x-1/4x-8+8=0
We multiply all the terms by the denominator
25x*4x-8*4x+8*4x-1=0
Wy multiply elements
100x^2-32x+32x-1=0
We add all the numbers together, and all the variables
100x^2-1=0
a = 100; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·100·(-1)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*100}=\frac{-20}{200} =-1/10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*100}=\frac{20}{200} =1/10 $

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