25x-33=6(3x-5)+7x-3

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Solution for 25x-33=6(3x-5)+7x-3 equation:



25x-33=6(3x-5)+7x-3
We move all terms to the left:
25x-33-(6(3x-5)+7x-3)=0
We calculate terms in parentheses: -(6(3x-5)+7x-3), so:
6(3x-5)+7x-3
We add all the numbers together, and all the variables
7x+6(3x-5)-3
We multiply parentheses
7x+18x-30-3
We add all the numbers together, and all the variables
25x-33
Back to the equation:
-(25x-33)
We get rid of parentheses
25x-25x+33-33=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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