25x-7=7/10x+11

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Solution for 25x-7=7/10x+11 equation:



25x-7=7/10x+11
We move all terms to the left:
25x-7-(7/10x+11)=0
Domain of the equation: 10x+11)!=0
x∈R
We get rid of parentheses
25x-7/10x-11-7=0
We multiply all the terms by the denominator
25x*10x-11*10x-7*10x-7=0
Wy multiply elements
250x^2-110x-70x-7=0
We add all the numbers together, and all the variables
250x^2-180x-7=0
a = 250; b = -180; c = -7;
Δ = b2-4ac
Δ = -1802-4·250·(-7)
Δ = 39400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{39400}=\sqrt{100*394}=\sqrt{100}*\sqrt{394}=10\sqrt{394}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-10\sqrt{394}}{2*250}=\frac{180-10\sqrt{394}}{500} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+10\sqrt{394}}{2*250}=\frac{180+10\sqrt{394}}{500} $

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