25x-8-19x=3(2x-4)+4

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Solution for 25x-8-19x=3(2x-4)+4 equation: 



25x-8-19x=3(2x-4)+4

We move all terms to the left:

25x-8-19x-(3(2x-4)+4)=0

We add all the numbers together, and all the variables

6x-(3(2x-4)+4)-8=0



We calculate terms in parentheses: -(3(2x-4)+4), so:

3(2x-4)+4

We multiply parentheses

6x-12+4

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

6x-6x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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