25x2+12x-13=11x-8-25x2

Solution for 25x2+12x-13=11x-8-25x2 equation:

25x^2+12x-13=11x-8-25x^2

We move all terms to the left:

25x^2+12x-13-(11x-8-25x^2)=0

We get rid of parentheses

25x^2+25x^2-11x+12x+8-13=0

We add all the numbers together, and all the variables

50x^2+x-5=0

a = 50; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·50·(-5)
Δ = 1001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1001}}{2*50}=\frac{-1-\sqrt{1001}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1001}}{2*50}=\frac{-1+\sqrt{1001}}{100}
$