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25x^2+17x-8=0
a = 25; b = 17; c = -8;
Δ = b2-4ac
Δ = 172-4·25·(-8)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-33}{2*25}=\frac{-50}{50} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+33}{2*25}=\frac{16}{50} =8/25 $
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