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25x^2+30x+7=0
a = 25; b = 30; c = +7;
Δ = b2-4ac
Δ = 302-4·25·7
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{2}}{2*25}=\frac{-30-10\sqrt{2}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{2}}{2*25}=\frac{-30+10\sqrt{2}}{50} $
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