25x2+40x+16=0

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Solution for 25x2+40x+16=0 equation: 



25x^2+40x+16=0

a = 25; b = 40; c = +16;
Δ = b2-4ac
Δ = 402-4·25·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{50}=-4/5$

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