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25x^2+40x+7=0
a = 25; b = 40; c = +7;
Δ = b2-4ac
Δ = 402-4·25·7
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-30}{2*25}=\frac{-70}{50} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+30}{2*25}=\frac{-10}{50} =-1/5 $
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