25x2+4=10X2+19

Solution for 25x2+4=10X2+19 equation:

25x^2+4=10x^2+19

We move all terms to the left:

25x^2+4-(10x^2+19)=0

We get rid of parentheses

25x^2-10x^2-19+4=0

We add all the numbers together, and all the variables

15x^2-15=0

a = 15; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·15·(-15)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*15}=\frac{-30}{30}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*15}=\frac{30}{30}
=1
$