25x2-1.44x+0.0064=0

Solution for 25x2-1.44x+0.0064=0 equation:

25x^2-1.44x+0.0064=0

a = 25; b = -1.44; c = +0.0064;
Δ = b2-4ac
Δ = -1.442-4·25·0.0064
Δ = 1.4336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.44)-\sqrt{1.4336}}{2*25}=\frac{1.44-\sqrt{1.4336}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.44)+\sqrt{1.4336}}{2*25}=\frac{1.44+\sqrt{1.4336}}{50}
$