25x2-100x+96=0

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Solution for 25x2-100x+96=0 equation:



25x^2-100x+96=0
a = 25; b = -100; c = +96;
Δ = b2-4ac
Δ = -1002-4·25·96
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20}{2*25}=\frac{80}{50} =1+3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20}{2*25}=\frac{120}{50} =2+2/5 $

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