25x2-10x-48=0

Solution for 25x2-10x-48=0 equation:

25x^2-10x-48=0

a = 25; b = -10; c = -48;
Δ = b2-4ac
Δ = -102-4·25·(-48)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-70}{2*25}=\frac{-60}{50}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+70}{2*25}=\frac{80}{50}
=1+3/5
$