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25x^2-225x=0
a = 25; b = -225; c = 0;
Δ = b2-4ac
Δ = -2252-4·25·0
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{50625}=225$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-225}{2*25}=\frac{0}{50} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+225}{2*25}=\frac{450}{50} =9 $
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