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25x^2-25x-5000=0
a = 25; b = -25; c = -5000;
Δ = b2-4ac
Δ = -252-4·25·(-5000)
Δ = 500625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500625}=\sqrt{5625*89}=\sqrt{5625}*\sqrt{89}=75\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-75\sqrt{89}}{2*25}=\frac{25-75\sqrt{89}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+75\sqrt{89}}{2*25}=\frac{25+75\sqrt{89}}{50} $
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