25x2-529=0

Solution for 25x2-529=0 equation:

25x^2-529=0

a = 25; b = 0; c = -529;
Δ = b2-4ac
Δ = 02-4·25·(-529)
Δ = 52900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{52900}=230$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-230}{2*25}=\frac{-230}{50}
=-4+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+230}{2*25}=\frac{230}{50}
=4+3/5
$