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25x^2-7=0
a = 25; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·25·(-7)
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{7}}{2*25}=\frac{0-10\sqrt{7}}{50} =-\frac{10\sqrt{7}}{50} =-\frac{\sqrt{7}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{7}}{2*25}=\frac{0+10\sqrt{7}}{50} =\frac{10\sqrt{7}}{50} =\frac{\sqrt{7}}{5} $
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