25x2=-35x+8

Solution for 25x2=-35x+8 equation:

25x^2=-35x+8

We move all terms to the left:

25x^2-(-35x+8)=0

We get rid of parentheses

25x^2+35x-8=0

a = 25; b = 35; c = -8;
Δ = b2-4ac
Δ = 352-4·25·(-8)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-45}{2*25}=\frac{-80}{50}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+45}{2*25}=\frac{10}{50}
=1/5
$