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25x^2=121
We move all terms to the left:
25x^2-(121)=0
a = 25; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·25·(-121)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*25}=\frac{-110}{50} =-2+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*25}=\frac{110}{50} =2+1/5 $
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