25x=(6x+4)(4x)

Solution for 25x=(6x+4)(4x) equation:

25x=(6x+4)(4x)

We move all terms to the left:

25x-((6x+4)(4x))=0


We calculate terms in parentheses: -((6x+4)4x), so:

(6x+4)4x

We multiply parentheses

24x^2+16x

Back to the equation:

-(24x^2+16x)


We get rid of parentheses

-24x^2+25x-16x=0

We add all the numbers together, and all the variables

-24x^2+9x=0

a = -24; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-24)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-24}=\frac{-18}{-48}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-24}=\frac{0}{-48}
=0
$