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25x=1.5x(x-1)
We move all terms to the left:
25x-(1.5x(x-1))=0
We calculate terms in parentheses: -(1.5x(x-1)), so:We get rid of parentheses
1.5x(x-1)
We multiply parentheses
x^2-1x
Back to the equation:
-(x^2-1x)
-x^2+25x+1x=0
We add all the numbers together, and all the variables
-1x^2+26x=0
a = -1; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-1)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-1}=\frac{-52}{-2} =+26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-1}=\frac{0}{-2} =0 $
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