25y+12=6(8y-4)-23y+36

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Solution for 25y+12=6(8y-4)-23y+36 equation: 



25y+12=6(8y-4)-23y+36

We move all terms to the left:

25y+12-(6(8y-4)-23y+36)=0



We calculate terms in parentheses: -(6(8y-4)-23y+36), so:

6(8y-4)-23y+36

We add all the numbers together, and all the variables

-23y+6(8y-4)+36

We multiply parentheses

-23y+48y-24+36

We add all the numbers together, and all the variables

25y+12

Back to the equation:

-(25y+12)



We get rid of parentheses

25y-25y-12+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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