25y+15-16y=7y+1(1/2)y-9

Solution for 25y+15-16y=7y+1(1/2)y-9 equation:

25y+15-16y=7y+1(1/2)y-9

We move all terms to the left:

25y+15-16y-(7y+1(1/2)y-9)=0


Domain of the equation: 2)y-9)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

25y-16y-(7y+1(+1/2)y-9)+15=0

We add all the numbers together, and all the variables

9y-(7y+1(+1/2)y-9)+15=0

We multiply all the terms by the denominator


9y*2)y-9)-(7y+1(+15*2)y-9)+1=0

We add all the numbers together, and all the variables

9y*2)y-9)-(7y+130y-9)+1=0

Wy multiply elements

18y^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{36}=0$