25y2+15y=-2

Solution for 25y2+15y=-2 equation:

25y^2+15y=-2

We move all terms to the left:

25y^2+15y-(-2)=0

We add all the numbers together, and all the variables

25y^2+15y+2=0

a = 25; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·25·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*25}=\frac{-20}{50}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*25}=\frac{-10}{50}
=-1/5
$