25z2=144

Solution for 25z2=144 equation:

25z^2=144

We move all terms to the left:

25z^2-(144)=0

a = 25; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·25·(-144)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*25}=\frac{-120}{50}
=-2+2/5
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*25}=\frac{120}{50}
=2+2/5
$