26(3y-9)=3(22y+2)

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Solution for 26(3y-9)=3(22y+2) equation: 



26(3y-9)=3(22y+2)

We move all terms to the left:

26(3y-9)-(3(22y+2))=0

We multiply parentheses

78y-(3(22y+2))-234=0



We calculate terms in parentheses: -(3(22y+2)), so:

3(22y+2)

We multiply parentheses

66y+6

Back to the equation:

-(66y+6)



We get rid of parentheses

78y-66y-6-234=0

We add all the numbers together, and all the variables

12y-240=0

We move all terms containing y to the left, all other terms to the right

12y=240

y=240/12

y=20

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