26(3y-9)=3(22y+3)

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Solution for 26(3y-9)=3(22y+3) equation:



26(3y-9)=3(22y+3)
We move all terms to the left:
26(3y-9)-(3(22y+3))=0
We multiply parentheses
78y-(3(22y+3))-234=0
We calculate terms in parentheses: -(3(22y+3)), so:
3(22y+3)
We multiply parentheses
66y+9
Back to the equation:
-(66y+9)
We get rid of parentheses
78y-66y-9-234=0
We add all the numbers together, and all the variables
12y-243=0
We move all terms containing y to the left, all other terms to the right
12y=243
y=243/12
y=20+1/4

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