26+2x=3(-x+5)-19

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Solution for 26+2x=3(-x+5)-19 equation: 



26+2x=3(-x+5)-19

We move all terms to the left:

26+2x-(3(-x+5)-19)=0

We add all the numbers together, and all the variables

2x-(3(-1x+5)-19)+26=0



We calculate terms in parentheses: -(3(-1x+5)-19), so:

3(-1x+5)-19

We multiply parentheses

-3x+15-19

We add all the numbers together, and all the variables

-3x-4

Back to the equation:

-(-3x-4)



We get rid of parentheses

2x+3x+4+26=0

We add all the numbers together, and all the variables

5x+30=0

We move all terms containing x to the left, all other terms to the right

5x=-30

x=-30/5

x=-6

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