26+x2=264

Solution for 26+x2=264 equation:

26+x2=264

We move all terms to the left:

26+x2-(264)=0

We add all the numbers together, and all the variables

x^2-238=0

a = 1; b = 0; c = -238;
Δ = b2-4ac
Δ = 02-4·1·(-238)
Δ = 952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{952}=\sqrt{4*238}=\sqrt{4}*\sqrt{238}=2\sqrt{238}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{238}}{2*1}=\frac{0-2\sqrt{238}}{2}
=-\frac{2\sqrt{238}}{2}
=-\sqrt{238}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{238}}{2*1}=\frac{0+2\sqrt{238}}{2}
=\frac{2\sqrt{238}}{2}
=\sqrt{238}
$