26-(2c+3)=2(c+4)+c

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Solution for 26-(2c+3)=2(c+4)+c equation: 


Simplifying
26 + -1(2c + 3) = 2(c + 4) + c

Reorder the terms:
26 + -1(3 + 2c) = 2(c + 4) + c
26 + (3 * -1 + 2c * -1) = 2(c + 4) + c
26 + (-3 + -2c) = 2(c + 4) + c

Combine like terms: 26 + -3 = 23
23 + -2c = 2(c + 4) + c

Reorder the terms:
23 + -2c = 2(4 + c) + c
23 + -2c = (4 * 2 + c * 2) + c
23 + -2c = (8 + 2c) + c

Combine like terms: 2c + c = 3c
23 + -2c = 8 + 3c

Solving
23 + -2c = 8 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
23 + -2c + -3c = 8 + 3c + -3c

Combine like terms: -2c + -3c = -5c
23 + -5c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
23 + -5c = 8 + 0
23 + -5c = 8

Add '-23' to each side of the equation.
23 + -23 + -5c = 8 + -23

Combine like terms: 23 + -23 = 0
0 + -5c = 8 + -23
-5c = 8 + -23

Combine like terms: 8 + -23 = -15
-5c = -15

Divide each side by '-5'.
c = 3

Simplifying
c = 3

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