26-(2c+3)=2(c+4)=c

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Solution for 26-(2c+3)=2(c+4)=c equation: 



26-(2c+3)=2(c+4)=c

We move all terms to the left:

26-(2c+3)-(2(c+4))=0

We get rid of parentheses

-2c-(2(c+4))-3+26=0



We calculate terms in parentheses: -(2(c+4)), so:

2(c+4)

We multiply parentheses

2c+8

Back to the equation:

-(2c+8)



We add all the numbers together, and all the variables

-2c-(2c+8)+23=0

We get rid of parentheses

-2c-2c-8+23=0

We add all the numbers together, and all the variables

-4c+15=0

We move all terms containing c to the left, all other terms to the right

-4c=-15

c=-15/-4

c=3+3/4

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