26-(2c+4)=2(c+3)+c

Solution for 26-(2c+4)=2(c+3)+c equation:

26-(2c+4)=2(c+3)+c

We move all terms to the left:

26-(2c+4)-(2(c+3)+c)=0

We get rid of parentheses

-2c-(2(c+3)+c)-4+26=0


We calculate terms in parentheses: -(2(c+3)+c), so:

2(c+3)+c

We add all the numbers together, and all the variables

c+2(c+3)

We multiply parentheses

c+2c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)


We add all the numbers together, and all the variables

-2c-(3c+6)+22=0

We get rid of parentheses

-2c-3c-6+22=0

We add all the numbers together, and all the variables

-5c+16=0

We move all terms containing c to the left, all other terms to the right

-5c=-16

c=-16/-5

c=3+1/5