26-(2c+4)=2(c+6)+c

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Solution for 26-(2c+4)=2(c+6)+c equation: 


Simplifying
26 + -1(2c + 4) = 2(c + 6) + c

Reorder the terms:
26 + -1(4 + 2c) = 2(c + 6) + c
26 + (4 * -1 + 2c * -1) = 2(c + 6) + c
26 + (-4 + -2c) = 2(c + 6) + c

Combine like terms: 26 + -4 = 22
22 + -2c = 2(c + 6) + c

Reorder the terms:
22 + -2c = 2(6 + c) + c
22 + -2c = (6 * 2 + c * 2) + c
22 + -2c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
22 + -2c = 12 + 3c

Solving
22 + -2c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
22 + -2c + -3c = 12 + 3c + -3c

Combine like terms: -2c + -3c = -5c
22 + -5c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
22 + -5c = 12 + 0
22 + -5c = 12

Add '-22' to each side of the equation.
22 + -22 + -5c = 12 + -22

Combine like terms: 22 + -22 = 0
0 + -5c = 12 + -22
-5c = 12 + -22

Combine like terms: 12 + -22 = -10
-5c = -10

Divide each side by '-5'.
c = 2

Simplifying
c = 2

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