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26-(2x+3)=2(x+4)+x
We move all terms to the left:
26-(2x+3)-(2(x+4)+x)=0
We get rid of parentheses
-2x-(2(x+4)+x)-3+26=0
We calculate terms in parentheses: -(2(x+4)+x), so:We add all the numbers together, and all the variables
2(x+4)+x
We add all the numbers together, and all the variables
x+2(x+4)
We multiply parentheses
x+2x+8
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
-2x-(3x+8)+23=0
We get rid of parentheses
-2x-3x-8+23=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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