26-(3+9y-4(y+5))=-5(5y-7)-(6(y-1)-20y+22)

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Solution for 26-(3+9y-4(y+5))=-5(5y-7)-(6(y-1)-20y+22) equation: 



26-(3+9y-4(y+5))=-5(5y-7)-(6(y-1)-20y+22)

We move all terms to the left:

26-(3+9y-4(y+5))-(-5(5y-7)-(6(y-1)-20y+22))=0



We calculate terms in parentheses: -(3+9y-4(y+5)), so:

3+9y-4(y+5)

determiningTheFunctionDomain
9y-4(y+5)+3

We multiply parentheses

9y-4y-20+3

We add all the numbers together, and all the variables

5y-17

Back to the equation:

-(5y-17)





We calculate terms in parentheses: -(-5(5y-7)-(6(y-1)-20y+22)), so:

-5(5y-7)-(6(y-1)-20y+22)

We multiply parentheses

-25y-(6(y-1)-20y+22)+35



We calculate terms in parentheses: -(6(y-1)-20y+22), so:

6(y-1)-20y+22

We add all the numbers together, and all the variables

-20y+6(y-1)+22

We multiply parentheses

-20y+6y-6+22

We add all the numbers together, and all the variables

-14y+16

Back to the equation:

-(-14y+16)



We get rid of parentheses

-25y+14y-16+35

We add all the numbers together, and all the variables

-11y+19

Back to the equation:

-(-11y+19)



We get rid of parentheses

-5y+11y+17-19+26=0

We add all the numbers together, and all the variables

6y+24=0

We move all terms containing y to the left, all other terms to the right

6y=-24

y=-24/6

y=-4

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