26-(32x-(1-x+2(18x-3)+6x))=12x-4

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Solution for 26-(32x-(1-x+2(18x-3)+6x))=12x-4 equation:



26-(32x-(1-x+2(18x-3)+6x))=12x-4
We move all terms to the left:
26-(32x-(1-x+2(18x-3)+6x))-(12x-4)=0
We get rid of parentheses
-(32x-(1-x+2(18x-3)+6x))-12x+4+26=0
We calculate terms in parentheses: -(32x-(1-x+2(18x-3)+6x)), so:
32x-(1-x+2(18x-3)+6x)
We calculate terms in parentheses: -(1-x+2(18x-3)+6x), so:
1-x+2(18x-3)+6x
determiningTheFunctionDomain -x+2(18x-3)+6x+1
We add all the numbers together, and all the variables
5x+2(18x-3)+1
We multiply parentheses
5x+36x-6+1
We add all the numbers together, and all the variables
41x-5
Back to the equation:
-(41x-5)
We get rid of parentheses
32x-41x+5
We add all the numbers together, and all the variables
-9x+5
Back to the equation:
-(-9x+5)
We add all the numbers together, and all the variables
-12x-(-9x+5)+30=0
We get rid of parentheses
-12x+9x-5+30=0
We add all the numbers together, and all the variables
-3x+25=0
We move all terms containing x to the left, all other terms to the right
-3x=-25
x=-25/-3
x=8+1/3

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