26-(3c+4)=2(c+5)+c

Solution for 26-(3c+4)=2(c+5)+c equation:

Simplifying
26 + -1(3c + 4) = 2(c + 5) + c

Reorder the terms:
26 + -1(4 + 3c) = 2(c + 5) + c
26 + (4 * -1 + 3c * -1) = 2(c + 5) + c
26 + (-4 + -3c) = 2(c + 5) + c

Combine like terms: 26 + -4 = 22
22 + -3c = 2(c + 5) + c

Reorder the terms:
22 + -3c = 2(5 + c) + c
22 + -3c = (5 * 2 + c * 2) + c
22 + -3c = (10 + 2c) + c

Combine like terms: 2c + c = 3c
22 + -3c = 10 + 3c

Solving
22 + -3c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
22 + -3c + -3c = 10 + 3c + -3c

Combine like terms: -3c + -3c = -6c
22 + -6c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
22 + -6c = 10 + 0
22 + -6c = 10

Add '-22' to each side of the equation.
22 + -22 + -6c = 10 + -22

Combine like terms: 22 + -22 = 0
0 + -6c = 10 + -22
-6c = 10 + -22

Combine like terms: 10 + -22 = -12
-6c = -12

Divide each side by '-6'.
c = 2

Simplifying
c = 2