26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17)

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Solution for 26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17) equation: 



26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17)

We move all terms to the left:

26-(4+6y-3(y+4))-(-5(5y-5)-(8(y-1)-27y+17))=0



We calculate terms in parentheses: -(4+6y-3(y+4)), so:

4+6y-3(y+4)

determiningTheFunctionDomain
6y-3(y+4)+4

We multiply parentheses

6y-3y-12+4

We add all the numbers together, and all the variables

3y-8

Back to the equation:

-(3y-8)





We calculate terms in parentheses: -(-5(5y-5)-(8(y-1)-27y+17)), so:

-5(5y-5)-(8(y-1)-27y+17)

We multiply parentheses

-25y-(8(y-1)-27y+17)+25



We calculate terms in parentheses: -(8(y-1)-27y+17), so:

8(y-1)-27y+17

We add all the numbers together, and all the variables

-27y+8(y-1)+17

We multiply parentheses

-27y+8y-8+17

We add all the numbers together, and all the variables

-19y+9

Back to the equation:

-(-19y+9)



We get rid of parentheses

-25y+19y-9+25

We add all the numbers together, and all the variables

-6y+16

Back to the equation:

-(-6y+16)



We get rid of parentheses

-3y+6y+8-16+26=0

We add all the numbers together, and all the variables

3y+18=0

We move all terms containing y to the left, all other terms to the right

3y=-18

y=-18/3

y=-6

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