26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17)

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Solution for 26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17) equation:



26-(4+6y-3(y+4))=-5(5y-5)-(8(y-1)-27y+17)
We move all terms to the left:
26-(4+6y-3(y+4))-(-5(5y-5)-(8(y-1)-27y+17))=0
We calculate terms in parentheses: -(4+6y-3(y+4)), so:
4+6y-3(y+4)
determiningTheFunctionDomain 6y-3(y+4)+4
We multiply parentheses
6y-3y-12+4
We add all the numbers together, and all the variables
3y-8
Back to the equation:
-(3y-8)
We calculate terms in parentheses: -(-5(5y-5)-(8(y-1)-27y+17)), so:
-5(5y-5)-(8(y-1)-27y+17)
We multiply parentheses
-25y-(8(y-1)-27y+17)+25
We calculate terms in parentheses: -(8(y-1)-27y+17), so:
8(y-1)-27y+17
We add all the numbers together, and all the variables
-27y+8(y-1)+17
We multiply parentheses
-27y+8y-8+17
We add all the numbers together, and all the variables
-19y+9
Back to the equation:
-(-19y+9)
We get rid of parentheses
-25y+19y-9+25
We add all the numbers together, and all the variables
-6y+16
Back to the equation:
-(-6y+16)
We get rid of parentheses
-3y+6y+8-16+26=0
We add all the numbers together, and all the variables
3y+18=0
We move all terms containing y to the left, all other terms to the right
3y=-18
y=-18/3
y=-6

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