26-11x=(4-x)(4-x)

Solution for 26-11x=(4-x)(4-x) equation:

26-11x=(4-x)(4-x)

We move all terms to the left:

26-11x-((4-x)(4-x))=0

We add all the numbers together, and all the variables

-11x-((-1x+4)(-1x+4))+26=0

We multiply parentheses ..

-((+x^2-4x-4x+16))-11x+26=0


We calculate terms in parentheses: -((+x^2-4x-4x+16)), so:

(+x^2-4x-4x+16)

We get rid of parentheses

x^2-4x-4x+16

We add all the numbers together, and all the variables

x^2-8x+16

Back to the equation:

-(x^2-8x+16)


We add all the numbers together, and all the variables

-11x-(x^2-8x+16)+26=0

We get rid of parentheses

-x^2-11x+8x-16+26=0

We add all the numbers together, and all the variables

-1x^2-3x+10=0

a = -1; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·(-1)·10
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*-1}=\frac{-4}{-2}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*-1}=\frac{10}{-2}
=-5
$