26-5(3-2z)=z-4(z-9)

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Solution for 26-5(3-2z)=z-4(z-9) equation:



26-5(3-2z)=z-4(z-9)
We move all terms to the left:
26-5(3-2z)-(z-4(z-9))=0
We add all the numbers together, and all the variables
-5(-2z+3)-(z-4(z-9))+26=0
We multiply parentheses
10z-(z-4(z-9))-15+26=0
We calculate terms in parentheses: -(z-4(z-9)), so:
z-4(z-9)
We multiply parentheses
z-4z+36
We add all the numbers together, and all the variables
-3z+36
Back to the equation:
-(-3z+36)
We add all the numbers together, and all the variables
10z-(-3z+36)+11=0
We get rid of parentheses
10z+3z-36+11=0
We add all the numbers together, and all the variables
13z-25=0
We move all terms containing z to the left, all other terms to the right
13z=25
z=25/13
z=1+12/13

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